Respuesta :
Answer: Choice B
Two imaginary solutions
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Explanation:
The given equation is
4x^2 - 3x + 1 = 0
Compare this to the general quadratic
ax^2 + bx + c = 0
to find that a = 4, b = -3, c = 1.
Plug those values into the discriminant formula below.
d = b^2 - 4ac
d = (-3)^2 - 4*4*1
d = 9 - 16
d = -7
Then recall that...
- If d > 0, then we have two real solutions.
- If d = 0, then we have only one real solution.
- If d < 0, then we have two imaginary solutions.
We see that d = -7 fits with the third option highlighted above.
4x2 – 3x + 1 =
- 0 one real solution
- two imaginary solutions
- one imaginary solution
- two real solutions
