Respuesta :

MissPhiladelphia
At 25.0∘C , the molar solubility of silver chromate in water is 1.10×10−12M. We calculate as follows:

1.10 x 10^-10 mol/L times 291.747 g/mol = 3.21 x 10^-8 g/L 

1.00 g divided by 3.21 x 10^-8 g/L = 3.12 x 10^7 L

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