Respuesta :

kaevras
[tex] \frac{9}{3- \sqrt{2} } [/tex]

You can rationalise this by multiplying the numerator and denominator by the denominator (inverse the sign).

[tex]\frac{9}{3- \sqrt{2} } * \frac{3+ \sqrt{2}}{3+ \sqrt{2}} = \frac{27+9 \sqrt{2}}{7} [/tex]


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