Answer:
[tex]-\frac{32}{3} x^9y^4[/tex]
Step-by-step explanation:
[tex](-\frac{4}{3} x^1y^3) (8x^8y^1)[/tex]
[tex]-\frac{4}{3}*8=-\frac{32}{3}[/tex]
[tex]x^1*x^8=x^{1+8} =x^9[/tex]
[tex]y^3*y^1=y^{3+1}=y^4[/tex]
[tex]-\frac{32}{3} x^9y^4[/tex]
Hope this helps!
