Answer:
two real zeros
[tex]x=-4+\sqrt{7}, -4=\sqrt{7}[/tex]
Step-by-step explanation:
1. 2 zeros, real
2. [tex](x+4)^2-7=0\\(x+4)^2 =7\\x+4=\pm\sqrt{7}\\x =-4\pm\sqrt{7}\\x=-4+\sqrt{7}, -4=\sqrt{7}[/tex]
