kaitlynneal5777 kaitlynneal5777

22-02-2022
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How many liters of 0. 1107 m kcl(aq) contain 15. 00 g of kcl?.

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spiderman62 spiderman62

22-02-2022

[tex]\huge \underline\frak \red{Answer}[/tex]

number of moles

N = sample mass/molar mass

N= 0.1107/74.6

N= 0.2010 moles of KCL

therefore

molarity = moles/volume

0.1107 = 0.2010/V

V = 0.2010/0.1107

V = 1.815L

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