shularja shularja

22-02-2022
Mathematics

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please helpppp btw not sure if the letter clicked is right or not it just won’t let me un select lol

please helpppp btw not sure if the letter clicked is right or not it just wont let me un select lol class=

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boatengalbert291 boatengalbert291

22-02-2022

Is wrong please
Answer is (a) 2

Proof
f(x)=(x^2) + 1.

g(x) = x + 2

f[g(-1)]

First considering g(-1)

g(-1)=(-1) + 2 = 1

f[g(-1)] = f(1)

=(1^2) + 1

=1+1=2

Hence f[g(-1)]=2

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