Answer:
49.37 g
Explanation:
So, Avogadro's number, which essentially acts as the definition of a mole, tells you that one mole of any ionic compound contains 6.022 × 10^23 formula units of that compound.
Remember that: one mole of any ionic compound contains 6.022 × 10^23 formula units
Step 1: You multiply the atoms of tellurium by 1 divided by the formula units
2.33 × 10^23 × 1 mole/6.022 × 10^23 formula units
= 0.386915 moles
Step 2: Find the molar mass of Tellurium
The molar mass of Tellurium is 270.60
Just search up the molar mass of Tellurium on Go.o.gle or look on a periodic table
Now we know that Tellurium has a molar mass of 127.60g. This means that every mole of Tellurium has a mass of 127.60g
Step 3: Next multiply the moles of Tellurium in step 1 by 127.60g divided by 1 mole
0.386915 moles × 127.60/1 mole
= 49.370354
49.37g
To check if this is correct
First Step: Mass or atoms→Moles
Step 1: To calculate the atoms of Tellurium, multiply the given grams by the reciprocal of the molar mass.
49.37g × 1 mol/270.60
= 0.386912 mol
Second Step: Moles→Atoms
Step 2: To calculate atoms of Tellurium, multiply moles Tellurium by Avogadro's number.
0.386912 mol × 6.022 × 10^23/ 1 mol
= 2.3299840639999997e+23
But the actual answer is 2.3299840639999997 rounded to the nearest hundredth or as other people may call it round to four significant figures
2.3299840639999997 rounded = 2.33
So the atoms of Tellurium is 2.33 × 10^23
So the answer "49.37g" is correct
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