Answer:
(3x +2)(x +1)
Step-by-step explanation:
A number of different ways are suggested for doing this. One that seems straightforward is this.
For ax^2 +bx +c, look for factors of ac that total b. Here we have ...
ac = 3·2 = 6
b = 5
It is easy to see that the factors we just multiplied to get 6 are ones that total 5: 3+2 = 5.
Now, rewrite the "bx" term using this sum.
3x^2 +3x +2x +2
Factor each pair of terms.
3x(x +1) +2(x +1)
And factor out the common factor:
(3x +2)(x +1)
