blakem1439 blakem1439
  • 24-11-2021
  • Mathematics
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sorry here is the question!! please help and Thank you!!

sorry here is the question please help and Thank you class=

Respuesta :

mathstudent55
mathstudent55 mathstudent55
  • 24-11-2021

Answer:

B.   4

Step-by-step explanation:

[tex] \dfrac{\sqrt{32}}{\sqrt{2}} = [/tex]

[tex] = \dfrac{\sqrt{16 \times 2}}{\sqrt{2}} [/tex]

[tex] = \dfrac{\sqrt{16} \times \sqrt{2}}{\sqrt{2}} [/tex]

[tex] = \dfrac{4\sqrt{2}}{\sqrt{2}} [/tex]

[tex] = 4[/tex]

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