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25-10-2021
Mathematics

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t (x) = 5x^2- 3x+4, what is the value t (-3)?

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Аноним Аноним

25-10-2021

the answer is t(-3) = 58

explanation:
t(x) = 5x^2 -3x +4
t(-3) = 5(-3)^2 -3(-3) +4
t(-3) = 5(9) -3(-3) +4
t(-3) = 45 + 9 + 4
t(-3) = 58

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