Answer:
B. 5Ω
Explanation:
Equivalent resistance between point P and Q
= 3Ω + Tp
Total Parallel resistance, Tp
[tex] \frac{1}{Tp} = \frac{1}{12Ω} + \frac{1}{6Ω} + \frac{1}{4Ω} [/tex]
[tex]\frac{1}{Tp} = \frac{1}{12Ω} + \frac{2}{12Ω} + \frac{3}{12Ω} [/tex]
[tex]\frac{1}{Tp} = \frac{6}{12Ω}[/tex]
[tex]6(Tp) = 12Ω[/tex]
[tex]Tp = \frac{12Ω}{6} [/tex]
[tex]Tp = 2Ω[/tex]
Equivalent resistance between point P and Q
= 3Ω + 2Ω
= 5Ω
