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In the diagram below, P is circumscribed about quadrilateral ABCD. What is the value of x?

In the diagram below P is circumscribed about quadrilateral ABCD What is the value of x class=

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x+10=90


x=80
Jim4109
When you have a quadrilateral inscribed in a circle the opposite angles are supplementary...they add to 180. 

x + 10 + 90 = 180
x + 100 = 180
x = 80 degrees

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