Answer:
[tex]\frac{BC}{sinA} = \frac{AB}{sinC}[/tex]
-> [tex]\frac{15}{sin98^{o}} = \frac{BC}{sin (180^{o} - 98^{o} - 45^{o}) }[/tex]
-> BC = 9. 11594... -> BC ≈ 9.1
hope it help u !!!
