sabaanwar9876
sabaanwar9876 sabaanwar9876
  • 24-08-2021
  • Chemistry
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6.3 gram of HNO3 as mass of nitrate

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Luongthanhnam40
Luongthanhnam40 Luongthanhnam40
  • 24-08-2021

Moles of HNO  3

​  = 6.3/63 = 0.1 moles  

HNO3  has 1 atom of H , 1 atom of N , 3 atoms of O

No of atoms = moles of molecule × atomicity of atom × avogadro number

No of atoms of H =0.1×1×6.023×10^23

 = 6.023×10^22  

 

No of atoms of N =0.1×1×6.023×10^23

 = 6.023×10  ^22

 

No of atoms of O =0.1×3×6.023×10  ^23

 =  18.069×10 ^22

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