12) Now,
n(U) = n.(A) + n.(B) + n(AnB) + n(AuB^_)
40 = 3x + 5 + 3x + 2 + 4 + x + 4
40 = 7x + 15
40 - 15 = 7x
◆ x = 5
◆ n.(A) = 3*5 + 5
= 20
◆ n.(B) = 3*5 + 2
= 17
◆ n(AuB^_) = 9
I hope you understand...
I hope it's help you...
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13) 27^x = 3^x+4
or, 3^3x = 3^x+4
or, 3x = x + 4
or, 3x - x = 4
or, 2x = 4
◆ x = 2
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