duttababita1975
duttababita1975 duttababita1975
  • 24-07-2021
  • Mathematics
contestada

Q: The value of
[tex] \sqrt{3 - 2 \sqrt{2} } [/tex]
is:->

(a)
[tex] \sqrt{2 } - 1[/tex]

(b)
[tex] \sqrt{2} + 1[/tex]

(c)
[tex] \sqrt{3} - \sqrt{2} [/tex]

(d)
[tex] \sqrt{3} + \sqrt{2} [/tex]
​

Respuesta :

Аноним Аноним
  • 31-07-2021

Answer:

A

Step-by-step explanation:

[tex]\sqrt{3-2*\sqrt2}=\sqrt{(\sqrt2)^2-2\sqrt2*1+1^2}=\sqrt{(\sqrt2-1)^2}=\sqrt2-1[/tex]

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