dianayanes87 dianayanes87
  • 25-06-2021
  • Mathematics
contestada

Somebody please help asap

Somebody please help asap class=

Respuesta :

akposevictor
akposevictor akposevictor
  • 01-07-2021

Answer:

B. [tex] 4x^2 + \frac{3}{2}x - 7 [/tex]

Step-by-step explanation:

[tex] f(x) = \frac{x}{2} - 3 [/tex]

[tex] g(x) = 4x^2 + x - 4 [/tex]

(f + g)(x) = f(x) - g(x)

= [tex] \frac{x}{2} - 3 + 4x^2 + x - 4 [/tex]

Add like terms

[tex] = 4x^2 + \frac{x}{2} + x - 3 - 4 [/tex]

[tex] = 4x^2 + \frac{3x}{2} - 7 [/tex]

[tex] = 4x^2 + \frac{3}{2}x - 7 [/tex]

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