nomunbiligm
nomunbiligm nomunbiligm
  • 24-06-2021
  • Mathematics
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PLEASE HELP MEE!! 50 POINTS
URGENT

The function y= x^2-10x+31 has a _____ (minimum, maximum) value of __ (5, 10, 31, 6)

PLEASE HELP MEE 50 POINTS URGENT The function y x210x31 has a minimum maximum value of 5 10 31 6 class=

Respuesta :

jimrgrant1 jimrgrant1
  • 24-06-2021

Answer:

minimum value of 6

Step-by-step explanation:

Given

y = x² - 10x + 31

with a = 1, b = - 10

Since a > 0 then the function has a minimum value

The minimum value is the y- coordinate of the vertex.

The x- coordinate of the vertex is

x = - [tex]\frac{b}{2a}[/tex] = - [tex]\frac{-10}{2}[/tex] = 5

Substitute x = 5 into the function for y- coordinate of vertex

y = 5² - 10(5) + 31 = 25 - 50 + 31 = 6

The function has a minimum value of 6

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