perezsept18 perezsept18
  • 23-06-2021
  • Mathematics
contestada

what is an equation of the line that is perpendicular to y + 1 = -3(x-5) and passes through the point (4, 6)

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CoastsideDad
CoastsideDad CoastsideDad
  • 23-06-2021

Answer:

y - 4 = 1/3(x-6)

Step-by-step explanation:

y-y₁=m(x-x₁)                 point slope formula

Substitute in the 4 and 6 for the [tex]x_{1}[/tex] and [tex]y_{1}[/tex]

Take the original slope of - 3 and change its sign and turn it into it's reciprocal

1/3

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