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22-06-2021
Mathematics

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How do you solve x[tex]x^{2} +4x+3=0[/tex]?

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Аноним Аноним

22-06-2021

Answer:

[tex]{ \tt{ {x}^{2} + 4x + 3 = 0}} \\ { \tt{(x + 1)(x + 3) = 0}} \\ \\ { \tt{x = - 1 \: \: and \: \: - 3}}[/tex]

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