Answer:
No real roots
Step-by-step explanation:
Given
[tex]6x^2 + 6x + 3 = 0[/tex]
Required
The number of solution
The discriminant (d) for [tex]ax^2 + bx + c = 0[/tex] is:
[tex]d = b^2 - 4ac[/tex]
So, we have:
[tex]d = 6^2 - 4*6*3[/tex]
[tex]d = 36 - 72[/tex]
[tex]d = -36[/tex]
Since [tex]d <0[/tex], then the equation has no real roots
