Answer:
Solution given:
A triangle PQR is right angled at R, with hypotenuse{h}PQ=80cm
and
base[b]PR=60cm.
perpendicular [P]= QR
by using Pythagoras law
h²=p²+b²
80²=QR²+60²
QR²=80²-60²
QR=[tex]\sqrt{2800}[/tex]
QR=20[tex]\sqrt{7}[/tex]=52.9=53cm
QR=53cm.
