Answer:
P₂ = 300 atm
Explanation:
Given that,
Initial volume, V₁ = 600 L
Initial pressure, P₁ = 400 atm
We need to find the pressure if the volume is 800 L.
We know that the relation between pressure and volume is given by :
[tex]P\propto \dfrac{1}{V}\\\\\dfrac{P_1}{P_2}=\dfrac{V_2}{V_1}\\\\P_2=\dfrac{P_1V_1}{V_2}\\\\P_2=\dfrac{600\times 400}{800}\\\\P_2=300\ atm[/tex]
So, the new pressure is equal to 300 atm.
