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Scores on a quiz are normally distributed with a mean of 78 and a standard deviation of 4. Find the percentage of scores for a randomly selected student with a score between 71 and 85.

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Answer:

[tex]p(71 < \times < 85) \\ = p( \frac{71 - 78}{4} < z < \frac{85 - 78}{4} ) \\ = p( - 1.75 < z < 1.75) \\ =1 - (\phi(1.75)) \\ = 0.46 \times 100\%\\ = 46\%[/tex]

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