hannapierceall
hannapierceall hannapierceall
  • 24-05-2021
  • Mathematics
contestada

use the quadratic formula x^2-5x+3=0

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sreedevi102
sreedevi102 sreedevi102
  • 24-05-2021

Answer:

[tex]x^2 -5x +3 = 0\\\\ x= \frac{-b \pm \sqrt{b^2-4*a*c} }{2a} \\\\b = -5, a = 1 , c = 3\\\\x= \frac{-b + \sqrt{b^2-4*a*c} }{2a} , x= \frac{-b -\sqrt{b^2-4*a*c} }{2a}\\\\x= \frac{5 + \sqrt{25-12} }{2}, x= \frac{5-\sqrt{25-12} }{2}\\\\x= \frac{5+\sqrt{13} }{2}, x= \frac{5- \sqrt{13} }{2}[/tex]

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