Answer:
Last option is the correct answer
[tex] (\sqrt[3]{2x - 6})^{3} = (- \sqrt[3]{2x + 6})^{3}[/tex]
Step-by-step explanation:
[tex] \sqrt[3]{2x - 6} + \sqrt[3]{2x + 6} = 0 \\ \sqrt[3]{2x - 6} = - \sqrt[3]{2x + 6}\\ cubing \: both \: sides\\ (\sqrt[3]{2x - 6})^{3} = (- \sqrt[3]{2x + 6})^{3}[/tex]
