contestada

Calculate the equivalent resistance of three resistances R1 = 2 Ω , R2 = 5 Ω and R3 = 11 Ω , if they are arranged such that the current flowing through all the three resistances is same.

Respuesta :

Answer:

The equivalent resistance is equal to 18 Ω.

Explanation:

The given resistors are 2 Ω, 5 Ω and 11 Ω.

They are arranged such that the current flowing through all three resistances is the same. It means the resistors are connected in a series combination.

The equivalent resistance in series combination is given by :

[tex]R_{eq}=R_1+R_2+....\\\\=2+5+11\\\\=18\ \Omega[/tex]

So, the equivalent resistance is equal to 18 Ω.

Otras preguntas