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Assume that the readings at freezing on a bundle of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find the probability of obtaining a reading greater than -0.084°C.
P(Z>-0.084)

Respuesta :

Answer:

0.53347

Step-by-step explanation:

We solve the above question using z score formula

z = (x-μ)/σ, where

x is the raw score = -0.084 °C

μ is the population mean = 0 °C

σ is the population standard deviation = 1°C

Z score =x - μ/σ

= -0.084 - 0/1

= -0.084

Probability value from Z-Table:

P(x<-0.084) = 0.46653

P(x>-0.084) = 1 - P(x<-0.084) = 0.53347

The probability of obtaining a reading greater than -0.084°C = P(x > -0.084) =

is 0.53347

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