Answer:
[tex]\Delta G =-103.95kJ[/tex]
Explanation:
Hello there!
In this case, since the thermodynamic definition of the Gibbs free energy for a change process is:
[tex]\Delta G =\Delta H-T\Delta S[/tex]
It is possible to plug in the given H, T and S with consistent units, to obtain the correct G as shown below:
[tex]\Delta G =-111.4kJ-(298K)(-25.0\frac{J}{K}*\frac{1kJ}{1000J} )\\\\\Delta G =-103.95kJ[/tex]
Best regards!
