Answer:
140 mol CO₂.
Explanation:
- 2 C₈H₁₈ + 25 O2 → 16 CO₂ + 18 H₂O
In order to convert from moles of octane (C₈H₁₈) into moles of CO₂, we can use a conversion factor with the stoichiometric coefficients of the balanced reaction:
- 17.5 mol C₈H₁₈ * [tex]\frac{16molCO_2}{2molC_8H_{18}}[/tex] = 140 mol CO₂
140 moles of CO₂ can be produced from 17.5 moles of octane.
