Answer:
[tex]P(C\ or\ D) = 1[/tex]
Step-by-step explanation:
Given
[tex]P(C) = \frac{3}{7}[/tex]
[tex]P(D) = \frac{4}{7}[/tex]
Required
[tex]P(C\ or\ D)[/tex]
Since the events are mutually exclusive, then:
[tex]P(C\ or\ D) = P(C) + P(D)[/tex]
So, we have:
[tex]P(C\ or\ D) = \frac{3}{7} + \frac{4}{7}[/tex]
Take LCM
[tex]P(C\ or\ D) = \frac{3+4}{7}[/tex]
[tex]P(C\ or\ D) = \frac{7}{7}[/tex]
[tex]P(C\ or\ D) = 1[/tex]
