Answer:
2513.41 mm³
Step-by-step explanation:
Given that,
The diameter of ball 1 = 39.5 mm
Radius of ball 1 = 19.75 mm
The volume of ball 1 is :
[tex]V_1=\dfrac{4}{3}\pi r^3\\\\=\dfrac{4}{3}\pi \times 19.75^3\\\\=32269.32\ mm^3[/tex]
The diameter of ball 2, = 40.5 mm
Radius = 20.25 mm
Volume of ball 2,
[tex]V_2=\dfrac{4}{3}\pi \times 20.25^3\\\\=34782.73\ mm^3[/tex]
Difference in volume = V₂ - V₁
= 34782.73 - 32269.32
= 2513.41 mm³
So, the difference in volume of the ball is equal to 2513.41 mm³.
