The answer is 1) (log4)5/(log4)6
We will use the change-of-base formula: [tex]log_a(x)= \frac{log_b(x)}{log_b(a)} [/tex]
So, if we want to write log6 5 as a logarithm of base 4. in these example a = 6, x = 5, b = 4:
[tex]log_6(5)= \frac{log_4(5)}{log_4(6)}[/tex]
