snulp3reenim snulp3reenim
  • 21-11-2016
  • Mathematics
contestada

Consider the function f(x) = ax+3 over x-b.
Find a and b given that y=f(x) has asymptotes with equations x = -1 and y = 2.

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HomertheGenius
HomertheGenius HomertheGenius
  • 21-11-2016
f ( x ) = ( a x + 3 ) / ( x - b )
Vertical asymptote: at x = - 1 the equation goes to infinity.
x - b = 0
- 1 - b = 0
- b = 1
b = - 1
Horizontal asymptote: at y = 2
[tex] \lim_{x \to \infty} \frac{ax+3}{x-b}=2 [/tex]
It means that a = 2.


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