Answer: 2.21 m/s
Explanation:
Given
Coin reaches a height of 0.25 m above the launch point
Suppose u is the initial speed of the coin
Using the equation of motion
[tex]\Rightarrow v^2-u^2=2as\\[/tex]
Putting values
[tex]\Rightarrow 0^2-u^2=2\times g\times s=2\times (-9.8)\times 0.25\\\Rightarrow u^2=4.9\\\Rightarrow u=2.21\ m/s[/tex]
Thus, the initial velocity is 2.21 m/s
