reesestebbs reesestebbs

22-03-2021
Chemistry

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Calculate the [OH-] in a solution that has a pH of 3.08.
a. 1.2x10-9
b. 8.3x10-3
C. 1.2x10-11
d. 8.3x10-4

Respuesta :

21ahmedfa 21ahmedfa

02-04-2021

Answer:

C. 1.2 x 10^-11

Explanation:

pOH = 14 - pH = 14 - 3.08 = 10.92

[OH-] = 10^-pOH = 10^-10.92 = 1.2 x 10^-11

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