Answer:
[tex]\frac{(x -7)(x-1)}{y}[/tex]
Step-by-step explanation:
[tex]x^{2}[/tex] / x - 1 - 6x - 7/ x - 1
(it's the equation shown in the picture, you might have typed it wrong on your question)
The equation has the same denominator so, it will become:
[tex]\frac{x^{2} - 6x - 7}{y}[/tex]
Which factors into:
[tex]\frac{(x -7)(x-1)}{y}[/tex]
