Explanation:
Given that,
The maximum range of a projectile is x.
Maximum range occurs when the angle of projection is 45°. Using formula for maximum range.
[tex]R=\dfrac{v^2}{g}[/tex]
According to the question,
[tex]x=\dfrac{v^2}{g}[/tex] ...(1)
Maximum height,
[tex]h=\dfrac{v^2}{2g}[/tex]
From equation (1).
[tex]h=\dfrac{x}{2}[/tex]
Hence, this is the required solution.
