Answer:
x²-(i-3)x- 3i
Step-by-step explanation:
What is a third-degree polynomial function P(x) with rational coefficients so that P(x) = 0 has roots −3 and i?
Given the toots of the polynomial to be -3 and i, the factors of the polynomial will be (x+3) and (x-i)
Taking the product
P(x) = (x+3)(x-i)
P(x) = x²-xi+3x-3i
P(x) = x²-(i-3)x- 3i
Hence the required polynomial is
x²-(i-3)x- 3i
