Answer:
[tex]y = \frac{1 }{8} {(x + 3)}^{2}[/tex]
Step-by-step explanation:
[tex]y = a(x - h)^{2} + k \\ y = a(x - ( - 3))^{2} + 0 \\ using \: points \: (1 ,\: 2) \\ 2 = a {(1 - ( - 3))}^{2} \\ 2 = a{4}^{2} \\ 16a = 2 \\ \boxed{ a = \frac{1}{8} } \\ hence \to \\ y = \frac{1}{8} (x - ( - 3))^{2} \\ y = \frac{{(x + 3)}^{2} }{8} [/tex]
