Answer:
at constant C = -56 satisfies the given condition of y(x)
Step-by-step explanation:
differentiate y(x) w.r.t.x
[tex]y' (x ) = \frac{d}{dx} (\frac{1}{4} x^5 +Cx^{-3} )[/tex]
= [tex]\frac{1}{4}\frac{d}{dx} (x^5) + C\frac{d}{dx} (x^{-3} )[/tex]
= [tex]\frac{5}{4} x^4 - 3Cx^{-4}[/tex]
attached is the remaining part of the detailed solution and the sketch of the several typical solutions
