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22-02-2021
Chemistry

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Write an equation that gives the overall equilibrium constant of 2Fe2O3+6C+3O2=4Fe+6CO2

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22-02-2021

Answer:

K = [Fe]4×[CO2] / [Fe2O3]2 × [C]6 × [O2]3

Explanation:

the over all reaction is

2Fe2O3(s) + 6C(s) + 3O2(g) ---> 4Fe(I) + 6CO2 (g)

So equilibrium constant equals, product concentration/ reactant concentration.

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