Answer:
Molarity[Na2S] = 0.1714
Molarity[Mgs] = 0.5811
Explanation:
Given:
0.300 mol [Na2S in 1.75 L]
31.3 g [MgS in 955 mL]
Find:
Molarity
Computation:
Molarity = Number of mole / volume in liter
Molarity[Na2S] = 0.300 / 1.75
Molarity[Na2S] = 0.1714
Molar mass of Mgs = 56.38 g/mol
Number of mole = 31.3 / 56.38
Number of mole = 0.555
Molarity[Mgs] = Number of mole / volume in liter
Molarity[Mgs] = [0.555 / 955]1000
Molarity[Mgs] = 0.5811
