Answer:
2,097,152
Step-by-step explanation:
Given the sequence
2, 8, 32, 128..
The sequence is a geometric sequence. The nth term of the geometric sequence is expressed as;
Tn = arⁿ⁻¹
a is the first term
r is the common ratio
n is the number of terms
From the sequence;
a = 2
r = 8/2 = 32/8 = 4
n = 11 (since we are to find the 11th sequence)
Substitute into the formula;
T₁₁ = 2(4)¹¹⁻¹
T₁₁ = 2(4)¹⁰
T₁₁ = 2(1,048,576)
T₁₁ = 2,097,152
Hence the 11th term of the sequence is 2,097,152
