Mass of water : 0.45 g
Further explanation
Given
1.5 g ethanoic acid
Required
Mass of water
Solution
Reaction
CH₃COOH + NaOH ⇒H₂O + CH₃COONa
mol CH₃COOH(MW=60 g/mol) :
= mass : MW
= 1.5 : 60
= 0.025
mol H₂O from the equation :
= 0.025(mol ratio CH₃COOH : H₂O= 1 : 1)
Mass of water :
= mol x MW water
= 0.025 x 18 g/mol
= 0.45 g
