Answer:
[tex]F=1.13\,*\,10^{15}[/tex] (answer a)
Explanation:
Recall the formula for the Coulomb force:
[tex]F=k\frac{q_1*q_2}{d^2}[/tex]
which in our case gives:
[tex]F=k\frac{q_1*q_2}{d^2} \\F=9*10^9\,\frac{63*45}{0.15^2} \\F\approx 1134000\,*\,10^9\\F\approx 1.13\,*\,10^{15}[/tex]
which agrees with answer a)
