Answer:
[tex]\alpha =1\ rad/s^2[/tex]
Explanation:
It is given that,
The radius of a wheel, r = 2 m
Tangential acceleration of the wheel, [tex]a=2\ m/s^2[/tex]
We need to find the angular acceleration of the wheel. We know that the relation between angular and tangential acceleration is given by :
[tex]a=\alpha r\\\\\alpha =\dfrac{a}{r}\\\\\alpha =\dfrac{2}{2}\\\\\alpha =1\ rad/s^2[/tex]
So, the angular acceleration of the wheel is [tex]1\ rad/s^2[/tex].
