Answer:
Q = 836 J
Explanation:
Given data:
Mass of water = 10.0 g
Temperature increased =ΔT = 20°C
Specific heat capacity of water = 4.18 J/g.°C
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Q = 10.0 g × 4.18 J/g.°C × 20°C
Q = 836 J
