Answer:
[tex]\huge\boxed{(f\circ g)(x)=8x-19}[/tex]
Step-by-step explanation:
[tex](f\circ g)(x)=f\bigg(g(x)\bigg)\\\\f(x)=4x-7;\ g(x)=2x-3\\\\\text{Put instead}\ x\ \text{expression}\ 2x-3\ \text{to }\ f(x):\\\\(f\circ g)(x)=4(2x-3)-7=(4)(2x)+(4)(-3)-7=8x-12-7=8x-19[/tex]
